What is the value of

44444445*88888885*444444442*44444438/44444448^2

a)88888883 b)88888884 c)88888888 d)44444443

• What is the value of
  
  44444445*88888885*44444442*44444438/44444448^2
  
  a)88888883 b)88888884 c)88888888 d)44444443
  
  take x=44444444
  thn given question can be written as
  (x+1)(2x-3)(x-2)+(x-6)/x^2
  
  solving we get 2x-5
  
  subt x=44444444 in 2x-5 we get ans as 88888883
  
  pls anyone solve that eqn and post
• 12 years agoHelpfull: Yes(23) No(13)
• What is the value of
  
  44444445*88888885*44444442*44444438/44444448^2
  
  a)88888883 b)88888884 c)88888888 d)44444443
  
  take x=44444444
  thn given question can be written as
  (x+1)(2x-3)(x-2)(x-6)/(x+4)^2
  After multiplaying we get
  2X^4-8X^3-28X^2+12X-36/X^2+16+8X
  solving we get 2x-5
  
  subt x=44444444 in 2x-5 we get ans as 88888883
  
• 12 years agoHelpfull: Yes(15) No(3)
• actual question is (44444445*88888885*444444442+44444438)/44444444^2.
  then x=44444444
  equation becomes
  =((x+1)*(2x-3)*(x-2)+(x-6))/x^2
  =((2x^2-x-3)(x-2)+(x-6))/x^2
  =(2x^3-4x^2-x^2+2x-3x+6+x-6)/x^2
  =(2x^3-5x^2)/x^2
  =2x-5
  =2(44444444)-5
  =88888888-5
  =88888883
• 11 years agoHelpfull: Yes(11) No(0)
• take the digit sum of all and compare with the digit sum from the ans..
• 10 years agoHelpfull: Yes(1) No(0)
• send me solution of this...
• 12 years agoHelpfull: Yes(0) No(2)
• Pls explain properly
• 11 years agoHelpfull: Yes(0) No(0)
• cant get ur answer
  
• 10 years agoHelpfull: Yes(0) No(0)