4 women and 6 men have to be seated in a row, given that no two women can sit together. How many different arrangements are there?

• correct ans is 6!*7P4
  i.e 60480
  n i bet this is the correct ans
  
• 12 years agoHelpfull: Yes(21) No(5)
• in 6 palce of men their are 7 place in which 4 women are sit so they are no sit togather.
  means
  _M1_M2_M3_M4_M5_M6_
  so 6 men sit in 6! ways and 7C4 ways sit women in which no 2 women sit togather.
  so total is 6!*7C4.
• 12 years agoHelpfull: Yes(20) No(11)
• yes the answer is 6!* 7P4....
  6 members can be seated in 6! ways.and in the 7 places 4 womenn have to be seated.this not selection of women.it is arrangement.so we should not use "C".we should use "P".therfore ans is 6!* 7P4
• 12 years agoHelpfull: Yes(12) No(4)
• here we have 6 men and 4 women.
  according to the question, first we sit 6 men there are 6 different ways to do this.
  when men get seated we have 7 different places between men for women.
  now we have to select 4 places from 7: 7C4
  so the answer is:6*7C4
• 12 years agoHelpfull: Yes(7) No(13)
• 6!*7c4
  first 6 men can be arranged in 6! ways
  as no two women together
  they can be arranged in 7c4 ways
  
• 12 years agoHelpfull: Yes(3) No(6)
• 6 MEN IN A row so there are 7 vacant where womens are placed
  so 6 men can arrange 6! ways
  and 4 women for 7 places can be arrange 7C4 ways
  and also they (4) are arrange them self in 4! ways
  so totall 6! * 7C4 * 4! ways they can arrange.
• 10 years agoHelpfull: Yes(3) No(1)
• 
  When all women when sit together MMMMMMWWWW
  No Of Ways: 7!*4!(6 MEN and all women as 1 Unit*No of ways of arranging Women)
  
  Total Ways: 10!
  
  Therefore No of ways when they dont sit together: 10!-7!*4!
• 12 years agoHelpfull: Yes(1) No(11)
• answer is= 10!-7!4!
• 12 years agoHelpfull: Yes(0) No(5)
• Let us first sit all the 6 men in 6 positions in 6! ways. Now there are 7 gaps between them in which 4 women can sit in 7P47P4 ways. So total ways are 6! x 7P4
• 8 years agoHelpfull: Yes(0) No(0)