In this question A B means A raised to the power B let f x 1 x x 2 x

There is a pattern.
if , f(x) = 1+x+x^2+.....+x^(n).
for x > 1,
then the remainder when f(x^(n+1)) is divided by f(x) is (n+1).
so , here remainder is 7.
10 years agoHelpfull: Yes(12) No(5)
to find remainder of a polynomial fn f(x)/g(x)
put x = 0,1 or any value

put x=0
f(x)=1
f(x^7)=1
f(x^7)/f(x)= 1/1 => remainder = 0

put x=1
f(x)=7
f(x^7)=7
f(x^7)/f(x)= 7/7 => remainder = 0
10 years agoHelpfull: Yes(8) No(6)
remainder is 0.
at x=1
f(x^7)/f(x)=1
10 years agoHelpfull: Yes(4) No(5)
ans d none of these

f(x^7)= 1+ x^7 + (x^7)^2 + .... + (x^7)^6
= 1+x^7 + x^14 + .... + x^4 = 1+x^7 * (1+x+x^2 + ... +x^6)
= 1+ x^7 f(x)
f(x^7)/f(x) = (1+ f(x)*x^7 ) / f(x)
the remainder is 1
10 years agoHelpfull: Yes(1) No(11)
remainder for f(x^1) is 1
and for f(x^2) is 2
than similarly,
for f(x^7) is 7
hence 7 is the answer
9 years agoHelpfull: Yes(1) No(2)
d..
let x=1..
then f(x)=7..
and
f(x^7)=8..thus we get,,
f(x^7)/f(x)=8/7=1
thus option is d
10 years agoHelpfull: Yes(0) No(2)
ans d none of these

f(x^7)= 1+ x^7 + (x^7)^2 + .... + (x^7)^6
= 1+x^7 + x^14 + .... + x^4 = 1+x^7 * (1+x+x^2 + ... +x^6)
= 1+ x^7 f(x)
f(x^7)/f(x) = (1+ f(x)*x^7 ) / f(x)
the remainder is 1
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9 years agoHelpfull: Yes(0) No(0)
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9 years agoHelpfull: Yes(0) No(0)

In this question A^B means A raised to the power B. let f(x)= 1+x+x^2+...x^6. The remainder when f(x^7) is divided by f(x) is:
a) 7
b) 0
c) 6
d) none of these