the letters in the word ROADIE are permuted in all possiible ways and arranged in alphabetical order. find thw word in 44 th rank

• arrange in alphabetic order
  ADEIOR
  now
  AD - - - - = 4! = 24
  AE D _ _ _ = 3! = 6
  AE I _ _ _ = 3! = 6
  AE o _ _ _ = 3! = 6
  till now we got 42 words (24+6+6+6)
  now 43 word will be
  AERDIO
  so 44 will be
  AERDOI
  
• 9 years agoHelpfull: Yes(29) No(11)
• A[DEIOR] =5!=120 NOT POSSIBLE
  AD[EIOR] = 4! = 24
  AE[DIOR] = 4! = 24
  AED[1OR] = 3! = 6+24=30
  AEI[DOR] =3! = 6+30 =36
  AEO[DIR] = 3! = 36+6 =42
  NOW 43RD LETTER WOULD BE AERDIO
  AND HENCE 44TH IS AERDOI
  
• 9 years agoHelpfull: Yes(12) No(0)
• given is ROADIE,need to arrange in this order ADEIOR
  so,
  to get the 1st letter A (present in 3rd position) =3! (now A_ _ _ _ _)
  2nd D(present in 3rd position after arranging A)=3! (AD_ _ _ _)
  3rd E(in 4th position after arranging AD)=4! (ADE_ _ _)
  4th I( in 3rd position)=3! (ADEI _ _)
  5th O(in 2nd position)=2! (ADEIO _)
  6th R(in 1st position)=1! (ADEIOR)
  so finally 3!+3!+4!+3!+2!+1=44
• 9 years agoHelpfull: Yes(4) No(6)
• @adity bhowmik plz read the question carefully,u misunderstood it.
• 9 years agoHelpfull: Yes(4) No(0)
• AEORID-42TH
  AERDIO-43TH
  AERIDO-44TH
• 9 years agoHelpfull: Yes(1) No(0)
• Solve by checking options....
  
  Suppose we have AERDOI in option
  A D R D O I
  5! 4! 3! 2! 1! 0!
  
  taking first alphabet A check how many alphabets are smaller than A. Here no alphabet is smaller than A so write zero(0) below A
  
  A D R D O I
  5! 4! 3! 2! 1! 0!
  0
  
  //ly check the other alphabets
  A D R D O I
  5! 4! 3! 2! 1! 0!
  0 1 3 0 1 0
  
  Ans is: 0*5! + 1*4! + 3*3! + 0*2! + 1*1! + 0*0! = 44
  so 44th word is AERDOI
• 9 years agoHelpfull: Yes(1) No(2)
• 
  AEROID=48th rank
  AERODI=47th ..
  AERIOD=46..
  AERIDO=45..
  AERDOI=44 th rank
• 9 years agoHelpfull: Yes(0) No(2)
• i cant understand what is meant by rank?can u plz explain it
  
• 9 years agoHelpfull: Yes(0) No(0)
• clearly explain it
  
• 9 years agoHelpfull: Yes(0) No(0)