There is a escalator and 2 persons move down it.A takes 50 steps and B takes 75 steps
while the escalator is moving down. Given that the time taken by A to take 1 step is equal to
time taken by B to take 3 steps. Find the no. of steps in the escalator while it is staionary.

• Let A take 1 step/min.
  Hence B takes 3 steps/min. Let the escalator take n steps/min
  Given that A takes 50 steps and hence in the same time escalator will
  take 50n steps. So total no. of steps must be 50 + 50n
  
  It is given that B takes 75 steps (which means he takes 25 min)
  So in the same time escalator will cover 25n steps.
  Hence no. of steps must be 75 +25n
  
  Equating 50+50n = 75+25n we get n = 1.
  Hence total no. of steps must be 100.
• 12 years agoHelpfull: Yes(18) No(0)
• x-50/x-75=3/1
  x=88
• 13 years agoHelpfull: Yes(2) No(12)
• suppose steps taken by B=75 at the same time by A=25 :( B=3A)
  that means a still have to cover 25 more steps
  (remove 25 from each which is due to escalator)
  now
  now the relativity of speed due to escalator will be B+E=2(A+E)
  or,3A+E=2A+2E
  , A=E
  so step covered by A and E was equal :50+50=100
  
  thank you hope i helped:)
• 10 years agoHelpfull: Yes(2) No(0)
• If A takes 1 step in one second, then B takes 3 steps in one second.
  If A takes t1 seconds to take 50 steps, then B takes 150 steps in t1 seconds.
  For B, to take 150 steps he requires t1 seconds,
  then to take 75 steps he requires t1/2 seconds.
  So now, s1=50, t1 = t1 & s2=75, t2=t1/2
  ans= (s1*t2 ~ s2*t1) / (t1 ~ t2) which gives 100.
  so 100 steps is the answer
• 6 years agoHelpfull: Yes(0) No(0)
• I didnt get it. can someone please explain it correctly.
  Thanku
• 5 years agoHelpfull: Yes(0) No(1)