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If the digits of my present age are reversed then i get the age of my son.If 1 year ago my
age was twice as that of my son.Find my present age.
ans. father-73, son-37
Read Solution (Total 1)
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- assume xy as the father's age. Now it can be written as (10x+y)
when the age of the father is reversed i.e yx it becomes son's age. So, son's age=(10y+x)
one year ago ages of father and son are (10x+y-1) and (10y+x-1) and they gave F=2S
(10x+y-1)=2(10y+x-1) --->8x=19y-1--->substitute x and y values for the eqn to get satisfied.
we get x=7,y=3 so, father=73,son=37 - 6 years agoHelpfull: Yes(0) No(0)
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