Raju can do a piece of work in 1o days,Vicky in 12days,Tinku in 15 days.They all started work together,but raju leaves after 2 days,vicky leaves 3 days before the work is completed. In how many days work is completed?
a)7 b)5 c)9 d)6

• Work done by Raju in 1 day=>1/10
  Work done by Vicky in 1 day=>1/12
  Work done by Tinky in 1 day=>1/15
  Initialy 3 of them work 2gether for 2 days...
  One of them leaves after that working for X days...
  at last only tinky remains n works for 3 days...
  So
  2*(1/10+1/12+1/15) + X*(1/12+1/15) + 3*(1/15)=1
  Solving :x=2
  
  Hence 2+2+3=7.
  Total work was done in 7 days...:)
• 12 years agoHelpfull: Yes(35) No(8)
• 7.after first iteration find out work done by tinku alone in 3 days
• 11 years agoHelpfull: Yes(1) No(3)
• Let the timw will taken by them to complete the whole work:x days.
  raju did the work for 2 days so:2/10
  vicky left the works 3 days before the work is completed,so:(x-3)/12
  Tinku did the rest of the works until the last day,so:x/15
  2/10+(x-3)/12+x/15=1
  x=7(ANS)
• 8 years agoHelpfull: Yes(1) No(0)
• total 7 days.
  
• 9 years agoHelpfull: Yes(0) No(2)
• pls explain clearly
  
• 8 years agoHelpfull: Yes(0) No(0)