A+B+C+D+E=FG,
FG =10F+G
A to G are different letters , if FG is as large as possible , what is value of G.

• 9+8+6+5+4=32 so ans should be 2
• 12 years agoHelpfull: Yes(8) No(1)
• 9+8+7+5+3=32...
  
  so answer is 2...
  
  
• 12 years agoHelpfull: Yes(6) No(7)
• if fg is a 2 digit no then its form is 10f +g then largest two digit no. is 98 for which f=9 and g is 8
  therefore it will be 8
  
• 12 years agoHelpfull: Yes(3) No(9)
• g=0....and FG=30...
• 12 years agoHelpfull: Yes(1) No(8)
• 
  pulkit if g is 0 then f*0 will be 0 lols
  
• 12 years agoHelpfull: Yes(1) No(8)
• Given A,B,C,D,E,F,G are different dights, assuming 9+8+7+2+5=31...where G=1 and is not repeating
• 12 years agoHelpfull: Yes(1) No(1)
• Given FG = 10F+G
  So, F * G = 10F +G
  =>G=9F+G
  
  Is this correct?
  
• 12 years agoHelpfull: Yes(0) No(13)
• pls send me all questions u have i have apti on 22 sept mumbai id- tjroxxy@gmail.com
• 12 years agoHelpfull: Yes(0) No(4)
• 9+8+6+5+4=32
  g=2,f=3
  satisfying fg=10f+g
• 12 years agoHelpfull: Yes(0) No(3)