112347..... ---
find the last three terms

• series is like 11,23,47.....
  then
  11*2+1=23
  23*2+1=47
  47*2+1=95
  95*2+1=191
  191*2+1=383
  hence,last three digit=95,191,383
• 12 years agoHelpfull: Yes(30) No(0)
• 6,11,8
  1st series is 1,2,4,6,8,......& so on
  2nd is 1,3,7,11,15........& so on
• 12 years agoHelpfull: Yes(1) No(5)
• the next three terms are 135,271,543
  11*2+1=23
  23*2+1=47
  47*2+1=135
  135*2+1=271
  271*2+1=543
• 12 years agoHelpfull: Yes(1) No(13)
• the ans is 1,1,2,3,4,7,8,15,16,31,32
  the alternative of the sequence was multiplied by 2 that is 1,2,4,8,16
  then,middle point have to cum the sequence like 2 ,4 ,8,16 ....by this we can find the adjacent of two numbers
• 12 years agoHelpfull: Yes(1) No(4)
• 1+1 = 2
  1+2 = 3
  1+3 = 4
  1+6 = 7
  1+12 = 13
  1+24 = 25
  1+48 = 49
• 12 years agoHelpfull: Yes(1) No(10)
• hmm...the numbers given here are fabonicci series..so the next three terms are 11,18.29..dats et
• 12 years agoHelpfull: Yes(0) No(2)