5 . A train approaches a tunnel AB. Inside the tunnel is a cat located at a point that is 3/8 of the distance AB measured from the entrance A. When the train whistles the cat runs. If the cat moves to the entrance of the tunnel, A, the train catches the cat exactly at the entrance. If the cat moves to the exit, B, the train catches the cat at exactly the exit. The speed of the train is greater than the speed of the cat by what order?
(3 : 1)

(4 : 1)

(5 :1)

(2:1)

none

• 
  
  
  
  
  
  
  
  Answer: b) 4 : 1
  
  D / v1 = (3/8) x / v2 ... ( 1 )
  
  ( D + x ) / v1 = (5/8) x / v2
  => D / v1 = (5/8) x / v2 - x / v1 ... ( 2 )
  
  From equns. ( 1 ) and ( 2 ),
  
  (3/8) x /v2 = (5/8) x / v2 - x / v1
  => 3 / (8v2) = 5 (8v2) - 1/ v1
  => 1 / v1 = ( 5/8 - 3/8) / v2
  => 4v2 = v1
  hence, answer will be 4:1
• 12 years agoHelpfull: Yes(38) No(4)
• Given two points of the tunnel A and B
  let us consider the distance between them is 8d
  given cat is at the distance 3d from th point A the left over distance to B is 5d
  let the train speed is T and cat speed is C
  if cat moves towards A then (T+C)*3d is the time taken to meet
  if it travels towards B then (T-C)*8d is the time taken to meet
  hence on solving above we get T/C is 4/1
  ans 4/1.
• 9 years agoHelpfull: Yes(2) No(0)
• wen d cat six ei
• 10 years agoHelpfull: Yes(1) No(5)
• 45559023hbjafhej33940-4
• 10 years agoHelpfull: Yes(1) No(5)