a woman travel from a to b at speed of x km/hr he then rest at b for x hr he then travel from bto c at speed of 2xkm/hr and rest for c for 2x hr he moves further to d at a speed
twice as that b/w b and c he thus resches d in 16 hr. if distance a-b,b-c, and c-d =12 km the time for which he rested at b could be.

• Just a calculation mistake
  12/x +x+12/2x +2x + 12/4x = 16
  21/x + 3x =16
  which give x equal to 3.
  So he rested at B for 3 hrs.
• 12 years agoHelpfull: Yes(8) No(0)
• 12/x +x+12/2x +2x + 12/4x = 16
  21/x + 3x =16
  which give x approx equal to 2.
  So he rested at B for 2 hrs.
• 12 years agoHelpfull: Yes(0) No(2)