A man goes to work daily. Everyday his wife picks him from railway station at 6 o'clock. One day, he left office early and reached the station at 5 o'clock. So, he started walking home. On the way, he met his wife, and they returned together in the car. They reached home ten minutes earlier than usual time. How much time did the man walk?

• 55 minutes
• 14 years agoHelpfull: Yes(14) No(18)
• explain clear answer
• 9 years agoHelpfull: Yes(12) No(5)
• the man leaves office 1 hr means 60 minute early..wife and man save 10 minutes..so if wife does not meat his husband then she has to go (10/2)=5 minutes more..so husband walk for(60-5)=55 minutes.
  
• 9 years agoHelpfull: Yes(9) No(8)
• In the que, sumthing is missing to get solution ocuratly....
  i thnk the speed of the man walk is missing in the que...
• 9 years agoHelpfull: Yes(7) No(6)
• Speed of man and car are missing. Time for which man walked, I think, will be 10*s(car)/s(man)
• 8 years agoHelpfull: Yes(0) No(0)
• Actually this is pure logical question,
  lets take Tminutes are usual time.
  but when he started at 5:00 and they just reached 10 minutes early
  that means here we have 60 minutes more.
  so [ Tminutes - 10/2 ]+ 60 = Tminutes + 55
  the reason for 10/2 is in this journey she started from her home after husband starts walking
  in this mean time we need not to take this 10 into account as in this 10 half time was in arrival and half is in departing from her husband.
• 8 years agoHelpfull: Yes(0) No(0)