What are the total number of divisors of 600(including 1 and 600)?
a) 24
b) 40
c) 16
d) 20

• Write the prime factorization.
  
  600 = (2^3)(3^1)(5^2)
  
  The number of divisors (including 1 and the number itself) is the product of one plus the exponents.
  
  (3+1)(1+1)(2+1) = 24
• 9 years agoHelpfull: Yes(26) No(0)
• The total no. of factors of a number N=a^p *b^q *c^r
  and the total no. of divisors=(p+1)*(q+1)*(r+1)
  so
  600=2^3 * 3^1 * 5^2
  total divisors=(3+1)*(1+1)*(2+1)=24
• 9 years agoHelpfull: Yes(7) No(1)
• N=a^p*b^q*c^r(factors)
  2^3*5^2*3^1=600
  N=(p+1)+(q+1)+(r+1)
  N=(3+1)*(2+1)*(1+1)
  N=24
  num of divisors =24
  
• 9 years agoHelpfull: Yes(3) No(0)
• 24 is answer.
  Factorize the 600..we get 2×2×2×5×5×3
  i.e 2^3,5^2,3^1
  Add 1 to the powers and multiply the powers
  (3+1)(2+1)(1+1)=24
• 9 years agoHelpfull: Yes(3) No(0)
• 600=2^3+3^1+5^2 (prime factor expansion)
  total number of factors=(3+1)*(1+1)*(2+1)=24
• 9 years agoHelpfull: Yes(0) No(0)