TCS Company Numerical Ability Arithmetic

two consecutive numbers are removed from the progression 1,2,3,...., n. The arithmetic mean of the remaining numbers is 26 1/4. The value of n is?

1)50 2)60 3)81 4)cannot be determined

Read Solution (Total 2)

n(n+1)/2 = 50*51/2 = 1275
1275-(x+x+1)/48 = 105/4
x = 7
Two consecutive no. are 7,8
Ans= 50
9 years agoHelpfull: Yes(9) No(7)

let choose from option:
take 50 as the ans
1,2,3,....50
sum= n(n+1)/2

50x51/2= 1275

if two consecutive no. are removed then
(1275-(x + x+1))/48=105/4
x=7
x+1=8
So, no. removed are 7 and 8. The correct option is 50.

Choosing other option gives you answer decimal point. Hence 50 is correct answer
9 years agoHelpfull: Yes(0) No(0)

TCS Other Question

If A^B means A raised to the power of B, in which of the following choices must P be greater than Q
a) 0.9^P=0.9^Q
b) 0.9^P=0.92^Q
c) 0.9^P>0.9^q
A^B means A raised to the power B. Let f(X)= 1+X,+X^2+.....X^6. The remainder when f(X^7
)is divided by f(X) is

1)7 2)0 3)6 4)none of these