A^B means A raised to the power B. Let f(X)= 1+X,+X^2+.....X^6. The remainder when f(X^7
)is divided by f(X) is

1)7 2)0 3)6 4)none of these

• Ans =7
  
  f(x)=1+x+x^2+.....x^6
  putting x=2
  f(x)=127
  
  
  f(2^7)=1+128+128^2+.....128^6
  
  dividing by 127
  f(128)=1/127+128/127+...128^6/127
  = 1 +1 + 1.....+1
  = 7
• 9 years agoHelpfull: Yes(17) No(2)
• to find remainder of a polynomial fn f(x)/g(x)
  put x = 0,1 or any value
  
  put x=0
  f(x)=1
  f(x^7)=1
  f(x^7)/f(x)= 1/1 => remainder = 0
  
  put x=1
  f(x)=7
  f(x^7)=7
  f(x^7)/f(x)= 7/7 => remainder = 0
• 9 years agoHelpfull: Yes(7) No(15)
• none of these
• 9 years agoHelpfull: Yes(2) No(3)
• ans will be 1....NONE OF THESE...
• 9 years agoHelpfull: Yes(0) No(4)
• i think none of these because if u put f(x) in the f(x^7) it will never be zero...so none of these.
• 9 years agoHelpfull: Yes(0) No(3)
• ans is none of these..
• 9 years agoHelpfull: Yes(0) No(0)
• ans is 7 .
  use the identity that x^n-a^n is always divisible by x-a
• 9 years agoHelpfull: Yes(0) No(0)
• Answer: C
  Explanation:
  Given that + ....+ =
  We will rewrite the above equation, ... +
  We know that
  ( = . )
  Now It is clear that is exactly divisible by f(x).
  Also and is a factor of this expression. ( is always divisible by
  Similarly, we write , ....
  So remainder = 1 + 6 = 7
• 9 years agoHelpfull: Yes(0) No(0)