train travelling at 90km/hr crosses goods train at 50km/hr in opposite direction completely in 50 sec.how long it takes train to overtake same goods train,if travellling in same direction?

• relative vel in first case - 140 kmph
  rel vel in second case = 40 kmph
  
  time taken in second case = 50*140/40 = 175 secs
• 12 years agoHelpfull: Yes(14) No(1)
• 175 sec
  length of train =t
  length of goods train=g
  t+g=(90+50)*(50/3600)km
  t+g=1.944444km
  now,t+g=(90-50)*tym
  tym=1.94444/40 hours
  tym=0.048611hours
  =0.048611*3600 secnd
  =175 sec
  
• 12 years agoHelpfull: Yes(6) No(2)
• when travelling in the same direction there relative speed is 140km/hr
  distance travelled =140*5=7000km
  since distance tavelled is same,and relative speed in same direction=40km/hr
  so time taken=7000/40=175sec
  
  
  
  
  
  
  
  
  
  
  
  
  
• 12 years agoHelpfull: Yes(4) No(7)
• Relative speed in 1st case=90-(-50)=140km/hr
  Relative speed in 2nd case=90-50=40km/hr
  so,140*50=40*x (x is d time taken in 2nd case)
  x=175secs..
  
• 12 years agoHelpfull: Yes(4) No(1)
• When the two trains are in opposite direction then relative speed is U+V
  When the two trains are in same direction then the relative speed is U-V
  First case=140km/hr
  Second case =40km/hr
  Distance travelled in first case d=tv [50/3600]*140=1.944km
  Distance travelled in second case d=tv
  T*40 km
  1.944=T*40
  T=0.0486hr
  Time in seconds =0.0486*3600
  175sec
  
  
• 12 years agoHelpfull: Yes(4) No(0)
• since time is in seconds,we will convert the speeds into m/s and den find answer...
  it should be 284 second approx.
  
• 12 years agoHelpfull: Yes(2) No(5)
• time is in seconds change d mistake frenz
  
• 12 years agoHelpfull: Yes(0) No(4)
• see first calculate their length that is 90+50=130*50/3600=1.94 kms
  then u have speed its 40kmps then 1.94/40=48 secs
• 12 years agoHelpfull: Yes(0) No(3)
• sorry then 1.94*3600/40 karo 175 aega and wo 90 + 50=140 tha :P
• 12 years agoHelpfull: Yes(0) No(2)