an elevator starts with 5 passengers and stops at different floors of house.find out probability of all 5 passengers alighting at different floors?

• when anyone can go on any floor then
  1st can go to any floor in n ways.
  2nd can go to any floor in n ways.
  3rd can go to any floor in n ways.
  4th can go to any floor in n ways.
  5th can go to any floor in n ways.
  so total no. of ways passenger alighting at floors = n*n*n*n*n = n^5
  
  now when they go to different floor then :-
  1st can go to any floor in n ways.
  2nd can go to any floor in n-1 ways.
  3rd can go to any floor in n-2 ways.
  4th can go to any floor in n-3 ways.
  5th can go to any floor in n-4 ways.
  so probabolity required will be = n*(n-1)*(n-2)*(n-3)*(n-4)/n^5
• 12 years agoHelpfull: Yes(32) No(5)
• It will depend on number of floors also which is not given.
  
  if there are n floors, then
  probability = n*(n-1)*(n-2)*(n-3)*(n-4)/n^5
• 12 years agoHelpfull: Yes(12) No(1)
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• 12 years agoHelpfull: Yes(0) No(10)
• plz explain formula?
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• Number of ways to select Mathematics is = 1
  Now student has to select 2 subjects out of remaining 5 subjects such that each selection includes Biology as one of the subject.
  This can be done by 4 ways i.e. Biology – Hindi, Biology – Physics, Biology – English and Biology – Chemistry.
  Hence, n (E) = 4
  And n (S) = 5C2 = 10
  Hence, the probability = 4/10=2/5
  
• 10 years agoHelpfull: Yes(0) No(0)