If it is a 3x3 matrix, for which elements
in first row are (V, 50, W), second row (196,
X, Y)and in third row are (269, Z, 123).It is
given that the sum of the numbers in each
row, column, diagonal are same. Then find
the value of (Y + Z).

• Ans : 1122
  
  matrix
  
  v 50 w
  196 x y
  269 z 123
  
  in 1st row and 1st column
  v+196+269=v+50+w
  w=415
  Again, in 2nd column and 3rd row
  50+x+z=269+z+123
  x=342
  
  As sum of each row column and diagonal are same.
  So, 269+342+415=1026
  415+y+123=1026
  y=488
  
  
  269+z+123=1026
  z=634
  
  y+z=488+634=1122
• 9 years agoHelpfull: Yes(31) No(1)
• v 50 w
  196 x y
  269 z 123
  v+50+w=v+196+269
  w=196+269-50
  w=465-50=415
  similarly
  v+x+123=w+x+269
  v=415+269-123
  v=561
  and
  so on
  ans is 1122
• 9 years agoHelpfull: Yes(1) No(0)
• ans is.1122
• 9 years agoHelpfull: Yes(1) No(0)
• Ans : 1122
• 9 years agoHelpfull: Yes(1) No(0)
• ans-1122
  matrix is
  v 50 w
  196 x y
  269 z 123
  
  then we make a equation x+50+z=269+z+123,
  then we get x=342,
  same as we get w=415,
  from v+342+123=50+v+w,
  then we get total of a diagonal 269+x+w=1026,
  then we get y=488,from equation w+y+123=1026,
  and get z =634,from 269+123+z=1026,
• 9 years agoHelpfull: Yes(0) No(0)
• v 50 w
  196 x y
  269 z 123
  this is the matrix assume sum is s
  by solving v+196+269=s and v+x+123=s
  we get x=342
  by solving w+y+123=s and w+322+269=s
  we get y=468
  then cal. sum and cal. z=614
  and the ans is y+z is 1082
• 9 years agoHelpfull: Yes(0) No(0)