Ram and Shakil run a race of 2000m. first, Ram gives shakil a start of 200m and beats him by 1 min. Next, Ram gives shakil a start of 6 min and is beaten by 1000m. Find the time in min in which Ram and Shakil can run the race separately
a)8,10
b)10,12
c)12,18
d)10,18

• ans >a
  Let x and y are the speeds of Ram and Shakil.. Then by problem we got following equation
  2000/x=(1800/y)-1
  1000/X=(2000/y)-6
  solve equation 1 and 2, we get x=250 and y=200
  Therefore, Time taken by Ram and Shakilk to complete a race of 2000m is 8 min and 10 Min
• 9 years agoHelpfull: Yes(11) No(0)
• Ans is b)
  1-as r gives start of 200m to s n beat him by 1min, so r covers 200m in 1min so to cover 2000m he will take 10 min
  2- as r gives 6min to s n beaten by 100m means s takes 6 min to cover 1000m so he will take 12min to civer 2000m
  so ans is b
• 9 years agoHelpfull: Yes(3) No(3)
• a/b=2000/(1800-b)=1000/(2000-6b)
  2000/(1800-b)=1000/(2000-6b)
  => 4000-12b=1800-b
  =>b=200
  
  Again,
  a/200=2000/(1800-200)
  =>a=250
  
  time taken by a(ram) 2000/250=8min
  time taken by b(shakil)= 2000/200= 10min
  
• 9 years agoHelpfull: Yes(1) No(1)
• D 1 =200+x D 2 =x per 1 min R-----------S---------X----------------------2000 for 1min
  200 m x m
  so for 1 min distence is 200+x and x their velocity are v1=(200+x) /1 v2=x/1 m/min
  given if S starts 6 min beaten by 1000m =>relative velocity=1000/6
  =>S covers for 1min x m =>6 min 6x
  relative velocity =[(200+x)-6x]/6=1000/6
  =>x=-180 from starting to 200 m then x=20m or D2=20m =>D1 220m for 1min
  V1=220/1 m/min V2=20/1 m/min
  =>t=D/V=> Rt=2000*1/220=100/11=9.99 min
  =>st=2000*1/20=100 min
  
• 9 years agoHelpfull: Yes(0) No(1)