Find the probability that a leap year chosen at random will have 53 sundays
a)2/7
b)1/7
c)1/49
d)3/7

• leap year=366 days
  after complete 52 weeks we have
  no. of odd days=366/7=2 days
  pairing of these 2 days could be possible as
  1[sun,mon] 2[mon,tue] 3[tue,wed] 4[wed,thu] 5[thu,fri] 6[fri,sat] 7[sat,sun]
  posiblity of sunday is 2 among 7 of these pairs
  so 2/7 is answer
• 10 years agoHelpfull: Yes(12) No(1)
• 2/7 . . . leap year has 366 days . . . 53 sundays will be there and 2 odd days .. . the probability of the odd days to be sunday is 2/7
• 10 years agoHelpfull: Yes(1) No(0)
• 2/7 ans..
  
  for leap year 52 weeks and 2 day more that may be sunday and monday or monday and tuesday or tuesday and wednesday...........like that saturday and sunday....son 2 sunday will be chosen from 7 guess...thats why probability 2/7
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• No of r
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• there are 7 days in week. so total number of possibilities are 7.
  in a leap year we have two odd days,out of 2 odd days one must be sunday
  therefore ans is 2/7
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• 2/7
  since every year has 52 weeks + 1 day
  since it is a leap year , 52 weeks +2 days
  all possoble 2 days pair
  sun,mon
  mon,tue
  tue,wed
  wed,thu
  thu,fri
  fir,sat
  sat,sun
  Prob.= no. of favourable outcomes/total no. of outcomes=> 2/7
• 9 years agoHelpfull: Yes(0) No(0)