thomas takes 7 days to paint a house completely whereas require 9 days to paint the same house completely.how many da7ys will take to paint the house if both them work together.

• work done by thomas in day=1/7
  work done by other in a day=1/9
  work done by both in a day=1/7 +1/9 =16/63
  days required by both = 63/16
• 9 years agoHelpfull: Yes(12) No(0)
• t=7d
  o=9d
  t+o=?
  find L.C.M for 7 and 9,we got 63.
  hence total work=63
  t=63/7=9 unit/day
  o=63/9=7 u/d
  so,t+o=16
  63/16=3.9
  
• 9 years agoHelpfull: Yes(3) No(1)
• 1/7 + 1/9 = 16/63
  the reciprocal of this is answer 63/16
• 9 years agoHelpfull: Yes(2) No(0)
• Approx 4 days..
• 9 years agoHelpfull: Yes(2) No(0)
• Direct trick
  X/7 + X/9 = 1
  16X / 63 = 1
  X=63/16
  This is applicable on all such questions
• 9 years agoHelpfull: Yes(2) No(1)
• 3.9days. thomos takes 7days to coplrte the work.so thomos 1 day work is 1/7 and another person one day work is 1/9.so for one day both of them combinely complete (1/7+1/9) work=16/63.total no.of days tocomplete work is 63/16 i,e;3.9.Approximately 4 days
• 9 years agoHelpfull: Yes(1) No(1)
• Don't know how to solve it pls give me a solution
• 8 years agoHelpfull: Yes(0) No(0)
• lcm of 7 and 9 gives toatal work i.e., work=63
  efficiency of 7=9
  efficiency of 9=7
  so if they both work togrther total work/total efficiency
  63/16=3.93 days
• 5 years agoHelpfull: Yes(0) No(0)
• thomas take 7 days to paint a house so in 1 day = 1/7
  other take p days to paint a house so in 1 day = 1/9
  if they work together = 1/7 + 1/9 = 16/63
• 5 years agoHelpfull: Yes(0) No(0)