0,1,2,3 use these numbers for 4digit numbers and find the sum?

• ans= 38664, just by forming all possibilities of 4 digit no
• 12 years agoHelpfull: Yes(10) No(2)
• formula is : (n-1)!*sum of digits*(1111....ntimes)
  
• 12 years agoHelpfull: Yes(7) No(5)
• Process of solving
  From these four digits '0' cannot be at first place to form four digit number
  so we have 1, 2, or 3 can be at thousand's place
  keeping one digit at thousand place can have 6 different four digit number
  so that means
  1000*6 + 2000* 6 + 3000* 6 = 36000
  
  Now come to hundred's place we can have all four digit at this place , '0' will not contribute any thing to sum so in all four digits number 1,2,3 will be at 4 times on same place
  so that means
  100*4 + 200* 4 + 300 * 4= 2400
  
  Now come to tenth's place ...same as hundred
  so
  10*4 + 20*4 + 30*4= 240
  
  same for unit place
  1*4 + 2*4 + 3*4= 24
  
  in last if you add whole the total sum of all possible four digit number formed is 38664
• 9 years agoHelpfull: Yes(3) No(0)
• if without repetition then sum is 66660
• 12 years agoHelpfull: Yes(1) No(6)
• 256
  4^4=256
• 12 years agoHelpfull: Yes(1) No(1)
• 4!*4!*4!*4!(ways of arrangmnt)*6(total sum)
  =1990656
• 12 years agoHelpfull: Yes(1) No(0)
• 1990656-24+24(for 1111,2222,3333,0000)
  =1990656
• 12 years agoHelpfull: Yes(1) No(0)
• bt how?
  ?????
• 12 years agoHelpfull: Yes(0) No(0)