A travels at 40kmph. B travels at 60kmph. They are travelling towards each other. BY the time they meet ,B would have travelled 120 km more than A. Find the total distance.

• dist. traveeld by A = 40x (let x be the time taken to meet)
  dist travelld by B = 60x
  difference in dist = 20x = 120; which gives x=6hours
  so relative speed of A and B is 100km/hr.
  distance travlld = 6*100 = 600km.
• 12 years agoHelpfull: Yes(37) No(4)
• Let, t is take taken to meet each other.
  Distance travelled by A=60t Km
  Distance travelled by B=40t km
  now, 60t-40t=120
  =>t=6 hour
  Total distance=60*6+40*6=600 Km
• 12 years agoHelpfull: Yes(22) No(0)
• A B
  1ST HR. 40KM 60
  2 80 120
  3 120 180
  4 160 240
  5 200 300
  6 240 360
  AFTER 6 HRS DIFFERENCE IN DISTANCE IS 120KM
  SO TOTAL DISTANCE IS 240+360=600KM
  
• 9 years agoHelpfull: Yes(9) No(0)
• let the distance traveled by A be = D
  then acc to question the distance traveled by B is = D+120
  now since the ratio of there speed is 2:3 which is the same for distance covered by each of them..
  as speed is directly proportional to distance ,
  2/3=d/d+120
  d= 240
  and total distance is d+d+120 = 240 +240+120 =600kms
• 9 years agoHelpfull: Yes(1) No(0)
• B will travel (60-40)=20 km more than A if distance bw them is 100 km. so, B will travel 120 km more than B if distance is 600km.
• 7 years agoHelpfull: Yes(0) No(0)