George can do 3 5 of work in 9days He then calls in pauls and they completed the work in

one day work of george=(3/5)/9=1/15
1 day work of george+pauls= (2/5)/4=1/10
1 day work of paul=(1/10)-(1/15)=1/30
so pauls takes 30 days to complete the work.
10 years agoHelpfull: Yes(6) No(0)
remaining work 2/5
to be completed in 4 days
george in 9 days - 3/5 part of work
george in 1 days - (3/5)*(1/9)=1/15
in 4 days -4/15 part work
so paul has to do 2/5-4/15 part work in 4days
=2/15 part work 4 days
1 part work in 30 days
9 years agoHelpfull: Yes(2) No(0)
30 days....
work done by George in 1day will be 1/15.
so it can be easily computed from that...
paul would take 30 days o complete the work
10 years agoHelpfull: Yes(0) No(9)
Paul will do work in xy/x-y days
15*10/5=30days
10 years agoHelpfull: Yes(0) No(0)
5/3*9=15
5/2*4=10
1/10-1/15=1/30
no of days=30
9 years agoHelpfull: Yes(0) No(0)
G -> 3/5 -> 9 -> 15 -> 6.66%
Remaining work is = 1-3/5=2/5
G+P -> 2/5 -> 4 -> 10 -> 10%
So, 10% - 6.66% = 3.34%
100/3.34 = 29.94
So the answer is : 30 days.
9 years agoHelpfull: Yes(0) No(0)

George can do 3/5 of work in 9days.He then calls in pauls and they completed the work in 4days.How long paul would take long to complete the work?
a)32
b)28
c)35
d)30