George can do 3/5 of work in 9days.He then calls in pauls and they completed the work in 4days.How long paul would take long to complete the work?
a)32
b)28
c)35
d)30

• George work is (5/3)*9 =15;
  1 day work of george is 1/15 ;
  remaining is 2/5th;
  paul & george work is 5/2*4=10 ;
  their 1 day work is 1/10;
  and only paul work is (1/10)-(1/15)=30
  answer: 30
• 9 years agoHelpfull: Yes(32) No(1)
• one day work of george=(3/5)/9=1/15
  1 day work of george+pauls= (2/5)/4=1/10
  1 day work of paul=(1/10)-(1/15)=1/30
  so pauls takes 30 days to complete the work.
• 9 years agoHelpfull: Yes(6) No(0)
• remaining work 2/5
  to be completed in 4 days
  george in 9 days - 3/5 part of work
  george in 1 days - (3/5)*(1/9)=1/15
  in 4 days -4/15 part work
  so paul has to do 2/5-4/15 part work in 4days
  =2/15 part work 4 days
  1 part work in 30 days
• 8 years agoHelpfull: Yes(2) No(0)
• 30 days....
  work done by George in 1day will be 1/15.
  so it can be easily computed from that...
  paul would take 30 days o complete the work
• 9 years agoHelpfull: Yes(0) No(9)
• Paul will do work in xy/x-y days
  15*10/5=30days
• 9 years agoHelpfull: Yes(0) No(0)
• 5/3*9=15
  5/2*4=10
  1/10-1/15=1/30
  no of days=30
• 8 years agoHelpfull: Yes(0) No(0)
• G -> 3/5 -> 9 -> 15 -> 6.66%
  Remaining work is = 1-3/5=2/5
  G+P -> 2/5 -> 4 -> 10 -> 10%
  So, 10% - 6.66% = 3.34%
  100/3.34 = 29.94
  So the answer is : 30 days.
• 8 years agoHelpfull: Yes(0) No(0)