A and B start simultaneously at one end of a swimming pool whose length is 50 m. The swimming race is a race of 1000 m. If A beats B and meets him 17 times during the course and A’s speed is 5 m/s then the speed of B could be
a) 1 m/s b) 3 m/s
c) 4 m/s d) 6 m/s

• the total distance of the pool is 50m.
  A will complete the race fully by 1000m.
  where as B will take nly (17*50)= 850m only.
  speed of A is 5 m/s => time taken to complete one round is 50m/(5m/s)=10 sec.
  the total time taken by A to complete the race is equal to the total time
  taken by B to complete 17th round.
  so (17Tb)=(20Ta)
  17Tb=(20*10)
  Tb=11.764 sec
  speed of B = 50/11.764 = 4.2 m/s..
  Option C will be rite..
• 11 years agoHelpfull: Yes(5) No(0)
• Total distance covered for 17 meet would be 34*50 = 1700 m
  
  The distance A wud travel 5*1700/(5+x), where 'x' is the speed of B.
  
  Now we know A travels 1000 m.
  
  8500/(5+x) = 1000
  
  => 8500-5000 = 1000x
  
  => x = 3500/1000 = 3.5 4
  
  So, option (C) wud be good choice.
• 11 years agoHelpfull: Yes(0) No(4)