To cars which are apart, move towards each other at the speed of 50 kmph and 60 kmph, the faster car travels 120 kms more than the other. Find the total distance traveled by the faster car.

• 120/10=12
  12*60=720
  
• 12 years agoHelpfull: Yes(15) No(1)
• let the dist travelled by slower car be==x
  dist travelld by faster== x+120
  time taken by cars to travel x and x+120 is the same
  therfore x/50=(x+120)/60
  solvin we get x=600
  therfore dist travelld by faster==x+120=600+120=720.
• 12 years agoHelpfull: Yes(9) No(1)
• 600km ratio prop
• 12 years agoHelpfull: Yes(6) No(11)
• faster car is 120/60=2hrs faster than the other car.
  their relative velocity is 50+60=110kmph
  so faster car goes 110*2=220km
  and as faster car is always 120km ahead
  so total distance covered by faster car is 220+120=340km
• 12 years agoHelpfull: Yes(2) No(8)
• Let the distance traveled by the first car be x km
  then distance covered by the second car is x + 120km
  x/50 = x+120 / 60
  x= 600
  so the distance between A & B is x + x + 120 = 1320 km
  
• 9 years agoHelpfull: Yes(2) No(0)
• 1080 km.......faster train moves 10 km more in 1hour
  then 120km=1/10*120= 12hour.and train are in opposite directions then r. speed =50+40=90km/h
  distance =s*t=90*12=1080km.
• 12 years agoHelpfull: Yes(1) No(11)