if A+B+C+D+E=FG, such that A,B,C,D,E are distinct numbers, where FG is in the form 10F+G, for FG to be the maximum possible value. What will be the value G be?

• Answer will be :
  9+8+7+5+2=31
  
  so, value of G=1.
• 12 years agoHelpfull: Yes(15) No(5)
• 9+8+7+6+5=35 therefore g=5
• 12 years agoHelpfull: Yes(10) No(11)
• 1............
• 12 years agoHelpfull: Yes(5) No(7)
• A+B+C+D+E=FG
  where FG=10F+G
  
  aply hit and trial and try to make combination such that A,B,C,D,E,F,G come out to be different number.
  so 9+8+7+5+2=10*3+1
  i.e A+B+C+D+E=10(F)+G
  
  therefore G=1
• 12 years agoHelpfull: Yes(5) No(2)