Two circles of radii 5 cm and 3 cm
touch each other at A and also touch a
line at B and C. The distance BC in cms
is?

• ans is sqrt(60)
• 9 years agoHelpfull: Yes(9) No(2)
• ans is sqrt(60)
  formula for the distance BC is = sqrt ( d^2 - ( (r1-r2)^2) ) where d=distance between two centers
• 9 years agoHelpfull: Yes(8) No(1)
• underroot 68
• 9 years agoHelpfull: Yes(7) No(2)
• the formula used here is √{ (D)^2 - (R-r)^2}
  here R=5 & r=3
  D=R+r
  So D=5+3 =8
  put in D=8 in above formula √{ (8)^2- (5-3)^2 } = √ { (64) - (2)^2 }= √ {64-4} =√ 60
  so answer is √60
• 9 years agoHelpfull: Yes(7) No(0)
• As radius are 5 and 3,
  distance between B and C is 5+3=8
• 9 years agoHelpfull: Yes(6) No(9)
• distance between bc is sqrt((distance between the centre)^2-(r1-r2)^2)
  i.esqrt(8^2-(2^2)
  i.esqrt(60)
• 9 years agoHelpfull: Yes(3) No(1)
• 8
  Its make a rectangle and bc is sum of both of both radius.
  
• 9 years agoHelpfull: Yes(1) No(2)
• sqrt(60) mark point over 5cm radius of 3 cm and joined it with c
  
• 9 years agoHelpfull: Yes(1) No(0)
• what is correct ans?? i solved this problem and ans is sq root of 68... is it correct??
• 9 years agoHelpfull: Yes(1) No(1)
• sqrt(d^2-(r1^2-r2^2)
  d=r1+r2=3+5=8
  sqrt(64-(25-9)^2)=sqrt(64-(16)^2)=sqrt(64-4)=sqrt(60)
• 9 years agoHelpfull: Yes(1) No(0)
• ans is sqrt(68)
• 9 years agoHelpfull: Yes(1) No(0)
• distance b/w b,c=sq.root of (d^2-(r1-r2)^2)
  where d= distance b/w 2 centers
  
• 9 years agoHelpfull: Yes(0) No(0)
• square root 60
• 9 years agoHelpfull: Yes(0) No(0)
• its sqrt(60)
• 9 years agoHelpfull: Yes(0) No(0)