3 persons are standing at the middle of edges of a Triangle.All the 3 persons starts moving at same time with same speed in random direction
What is the probability of meeting atleast 2 persons?

• question is incomplete hint is given like this ......every ant has two possibilities it should move towards any other vertices ......so here it is clear that every ant has 2 possibilities so total no of possibilities are 2*2*2=8.
  the ants do not collide only when they all move in clockwise or all move in anticlock wise direction so remove those possibilities =8-2=6
  so.,6/8 is the req ans
• 6 years agoHelpfull: Yes(8) No(0)
• no of times that they dont meet is 2
  so they meet in 6 ways
  so required probability is=6/8=3/4
• 9 years agoHelpfull: Yes(6) No(3)
• can u explain it??
  
• 9 years agoHelpfull: Yes(3) No(0)
• prob. of meeting any two persons is 3/8
• 9 years agoHelpfull: Yes(2) No(9)
• can anyone explain this??
  
• 9 years agoHelpfull: Yes(1) No(1)
• answer will be 3/4 as total no. of cases of possible moves=8
  from this in 2 case their will not be collision(all anti clock or all clock wise)
  
  so,p=(8-2)/8=3/4
• 9 years agoHelpfull: Yes(1) No(1)
• No. of events will be 8. This is because the person can move either inside or outside the triangle.
  And the no. of favorable events will be 6. This is because we want at least 2 person to meet and we have total 3 person, so 2x3 = 6
  
  Probability = 6/8 = 3/4
  Ans= 3/4
• 9 years agoHelpfull: Yes(1) No(0)