A journey of 600 km, Due to some problem in Vehicle speed was reduced to 200 kmph and it takes 30min extra, Find the Actual time taken for Journey?

• reduced to 200 & reduced by 200 are completely different...
  improve ur language.....!
• 9 years agoHelpfull: Yes(16) No(5)
• Here the Distance is constant. So, let the actual time is x.
  Then,
  600/x-600/(x+(1/2))=200
  After we solve this we will get 1hr.
  So, the actual time taken for the journey is 1hr.
  
• 9 years agoHelpfull: Yes(13) No(7)
• Let the actual speed be x kmph. As the time taken increases by 30minutes as speed is decreased by 200kmph, so...
  
  600/(x-200) - 600/x = 30/60
  
  we get x= 600kmph
  so, actual speed= 600kmph
  therefore, actual time taken= 600/600= 1 hour
• 9 years agoHelpfull: Yes(9) No(9)
• Ans=2hr 30 min.
  actual speed is 240kmph
  600/(x+200) =600/200+30/60
  x=40
• 9 years agoHelpfull: Yes(9) No(5)
• The actual time is 2hr and30 min because if it travels with a speed of 200kmph it reach 30min late by that we came to know if it travels 240kmph then it will reach 30min before that time of speed 200kmph
• 9 years agoHelpfull: Yes(2) No(1)
• Let the duration of the vechicle be x hours.
  
  Then, 600/x - 600/ [x + (1/2)] = 200
  
  600/x -1200/(2x + 1) = 200
  
  x(2x + 1) = 3
  
  2x^2 + x - 3 = 0
  
  (2x + 3)(x - 1) = 0
  
  x = 1 hr. [neglecting the -ve value of x]
  ans is 1hr
• 6 years agoHelpfull: Yes(2) No(1)
• Let the duration of the journey be x hours.
  
  Then, 600 - 600 = 200
  x x + (1/2)
  
  600 - 1200 = 200
  x 2x + 1
  
  x(2x + 1) = 3
  
  2x2 + x - 3 = 0
  
  (2x + 3)(x - 1) = 0
  
  x = 1 hr.
• 9 years agoHelpfull: Yes(0) No(5)
• Ans: 240 km/h
  
• 9 years agoHelpfull: Yes(0) No(4)
• let the original speed =s,original time =t i.e s=d/t that means => s=600/t.................(1)
  => (s-200)=600/(1/2)............(2) as time 30 min in hrs
  by solving these two eqtns we get original time t=1 hrs.
  
• 9 years agoHelpfull: Yes(0) No(3)