remainder of (6^17+ 17^6)/7 ?
options-
1, 6, 0 ,3

• remainder when 6^17 + 17^6 is divided by 7
  6^17mod7....>(7-1)^17mod7=(-1)^17(because 7^17 is divisible by 7 ,so we avoid it and only take (-1)^17 mod 7=-1 .........(1)
  17^6....>(7*2+3)^6 mod7=(3)^6 mod 7....729 mod 7=1 .......(2)
  so now remainder when 6^17 + 17^6 is divided by 7
  now eq (1)+(2) mod 7
  (6^17 + 17^6)mod 7=(-1+1) mod 7=0 mod 7=0
  ans is 0.
  
• 12 years agoHelpfull: Yes(22) No(3)
• 6^17 its unit digit is 6 and 17^6 its unit digit is 9 .according to the cyclicity of 6 in1st part and 7 in 2nd part .
  6+9/7=15/7=1 is the remainder
• 12 years agoHelpfull: Yes(4) No(13)
• 32+16+8=56
• 12 years agoHelpfull: Yes(0) No(0)