If age of a person is x and his mothers age is 34. then after how many years will the mothers age be twice of the son?

• let sons AGE=x, mother age=34.
  from the given information we get
  2(x+y)=34+y. solving this
  2x+y=34.
  so x= 15 and y=4 suitable. check it for after 4 years 15+4=19.
  i. e 2(19)= 34+4= 38. after 4 years
  mother is double of sons age.
• 11 years agoHelpfull: Yes(14) No(5)
• insufficient data
• 12 years agoHelpfull: Yes(12) No(0)
• 2(x+Y)=34+Y
  Y=34-2x
• 11 years agoHelpfull: Yes(9) No(0)
• Answer of this question based on option which u given..
  
  
• 12 years agoHelpfull: Yes(7) No(1)
• Ans will be according to the option..bt eqn will be 2(x+y)= (34+y)
  y= no of years ask in question.
• 11 years agoHelpfull: Yes(5) No(0)
• @ to option u can give solution
  
  34=2*x+y
  
  so more than 1 combination are possible
  
  x=15,y=4 so 4 years
  x=16 ,y=2 so 2 years
• 10 years agoHelpfull: Yes(4) No(0)
• The eqn that can be formed from this question is
  2x-34=y, where y being the no. of years that are needed.
  So,give the options or data is incomplete.
• 12 years agoHelpfull: Yes(1) No(4)