closed cylindrical tank contains 36pi cubic feet of water and its filled to half its capacity. When the tank is placed upright on its circular base
on level ground, the height of water in the tank is 4 feet. When the tank is placed on its side on level ground, w hat is the height, in feet, of the
surface of the water above the ground?

• We know that the volume of cylinder = πr^2h
  Given tank height = 4ft.
  ⇒ π r^2 4 = 36π
  ⇒ r = 3
  So the radius is 3 which means the diameter is 6.
  As the cylinder is filled to initially exactly half of the capacity, When this cylinder is placed on its side, Water comes up to the height of the radius.
  So water comes up to 3 ft
• 9 years agoHelpfull: Yes(7) No(4)
• 3 ft....
  radius will become height
  
• 9 years agoHelpfull: Yes(0) No(0)
• Here in this problem when the tank is filled to half of its capacity the height of water in the tank is 4 feet.then how the height of the tank can be 4 feet in the solution??
• 9 years agoHelpfull: Yes(0) No(0)
• It should be noted that since the cylindrical tank is half filled to its capacity, when placed on its side also it will be filled to half its capacity.
  Volume of the water in the cylinder in upright position is (pir2h). This is equal to 36pi.
  Thus we have an equation pir2h = 36pi.
  We are given ‘h’ is equal to 4. Applying this value we will have r2 = 9 and r = 3. ie half the base.
  When the cylinder is placed on its side the water level will be only upto this height.
  Hence the answer is 3 feet.
• 8 years agoHelpfull: Yes(0) No(0)