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Numerical Ability
Algebra
If a, b ,c are + ve integers and 28a +30b + 31c= 365 then a+ b+ c=
a 12
b <= 11
c >13
d 13
Read Solution (Total 7)
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- this question is related to months of a year.
there is 1 month that is february with 28 days, 7 months with 31 days and 4 months with 30 days.
therefore answer is 1+7+4=12. Equal to 12 months in a year.
So, 28(1)+30(4)+31(7)= 365 days. - 9 years agoHelpfull: Yes(17) No(0)
- answer is 12
soln: take months a=1,b=4,c=7
1+4+7=12 - 9 years agoHelpfull: Yes(2) No(0)
- Ans:(a)12
28 days=feb=1
31 days=jan,mar,may,july,aug,oct,dec=7
30days=april,june,sep,nov=4 - 9 years agoHelpfull: Yes(1) No(0)
- 12 is the answer
as a+b+c can be the total number of months in a year - 9 years agoHelpfull: Yes(0) No(0)
- only feb-- 28 day-- means. a=1
jan ,march , may ,jul ,aug, oct ,dec are -- =31 day.means - c=7
apr, jun ,sept ,nov are ==30 days...means b= 4
- 9 years agoHelpfull: Yes(0) No(0)
- answer a because their are 1 month witch has 28 days and remaining 11 has 30 and 31
- 9 years agoHelpfull: Yes(0) No(1)
- ans:12
cosider the days of the month
28= feb=1
30=april,june,sep,nov=4
31=jan,mar,may,july,aug,oct,dec=7
totally=1+4+7=12
- 9 years agoHelpfull: Yes(0) No(0)
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