what is the 10 th term in 1,3,9,15,25,35,-----?

• 1^2 =1
  2^2 -1 =3
  3^2 =9
  4^2 -1 =15
  5^2 =25
  6^2 -1 =35
  7^2 =49
  8^2 -1 =63
  9^2 =81
  10^2 -1=99
• 9 years agoHelpfull: Yes(37) No(1)
• 10th term will be 49...
  1+2=3
  3+6=9
  9+6=15
  15+10=25
  25+10=35
  35+14=49
  (2,6,6,10,10,14,14,18,18.................and so on ithink
  
• 9 years agoHelpfull: Yes(12) No(9)
• Difference b/w the digits in a order like- 1-3=2; 9-3=6; 15-9=6; 25-15=10; 35-25=10; so this type series will continue in the same order - 2,6,6,10,10,14,14,18,18,22. So the new series will be 1,3,9,15,25,35,49,63,81,99,121.
  121 will be the 10th term of the given series.
• 9 years agoHelpfull: Yes(6) No(1)
• 10 th term will be 99.
• 9 years agoHelpfull: Yes(5) No(0)
• why can not we take the difference as 2,6,6,10,10,10,14,14,14,14,18,18-------
  every time one term is increasing that first one 2,two 6s,three 10s,four 14s
• 9 years agoHelpfull: Yes(3) No(0)
• 1, 3 , 9, 15, 25, 35, 49, 77, 121, 143
  1^2 __3^2__5^2__7^2__11^2__13^2
  3 15 35 77 143
• 9 years agoHelpfull: Yes(2) No(0)
• 1^2,1*3,3^3,3*5,5^2,5*7,7^2,7*9,9^2,9*11,11^2.....
  so the 10th term will be 121
• 9 years agoHelpfull: Yes(1) No(0)
• is 121 a 10th term or 11th term??
  
• 9 years agoHelpfull: Yes(1) No(0)
• Ans: 49
  1=1^2, 3=(2^2)-1, 9=3^2, 15=(4^2)-1...... so 49=7^2
• 9 years agoHelpfull: Yes(1) No(0)
• Difference between the digits is 2,6,6,10,10 so the next numbers difference is 14,14,18,18 and so on
• 9 years agoHelpfull: Yes(0) No(0)
• Firstly difference between each number is taken as
  3-1=2,9-3=6, 15-9=6,25-15=101,35-25=10, so in the same way this series will continue..so the next no.should have difference of 14...therfore 35+14=49,49+14= 63,
  63+18=81, 81+18=99,99+22=121
  so the 10 thno.wil be 121
• 9 years agoHelpfull: Yes(0) No(1)
• Your said that only 7th term only@Dorababu
• 9 years agoHelpfull: Yes(0) No(0)
• 99 i.e 10*10-1
• 9 years agoHelpfull: Yes(0) No(0)
• divide into two series odd place and even place
  odd:1^2,3^2,5^2,7^2,9^2.......
  even:2^2-1,4^4-1,6^2-1,8^2-1,10^2-1...
  ans:100-1=99
• 9 years agoHelpfull: Yes(0) No(0)
• 1 3 9 15 25 35
  - - - - -
  2 6 6 10 10
  
  after repeating the digit twice then 4 to them as given
  
  1 3 9 15 25 35 49 63 81 99
  - - - - - - - - -
  2 6 6 10 10 14 14 18 18
  
  ans: 99
• 6 years agoHelpfull: Yes(0) No(0)