If a swimming pool is surrounded by a cement floor of 4 feet wide and the difference between the circumference of both swimming pool and cement floor is 11/25th of area of swimming pool, what is the radius of swmming pool?

• 4.26 sqrt((25*8)/11)
  
• 11 years agoHelpfull: Yes(25) No(3)
• r=10surt2/11
  =1.2856
• 11 years agoHelpfull: Yes(5) No(6)
• saurabh..i cant understand..can you explain it properly?
• 11 years agoHelpfull: Yes(3) No(1)
• @uma: hmmmm let me explain
  let swm pl radios =x
  then including outer cement floor the radios will be x+4
  now according to question
  circumference(outer circle )-circumference (inner circle )=(circumference (inner circle )*11/4
  circumference(outer circle )=2*pi*(x+4)
  circumference(outer circle )=2*pi*(x)
  put the vale
  you will get the ans
  
  
• 11 years agoHelpfull: Yes(3) No(4)