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Permutation and Combination
there are 4 couples came to honeymoon and they all have to cross a river, theres only one boat, and the wives are jealous that they dont like there husbands travellng with other women, husbands are possesive that they dont like their wives travelling with other man. the number of minimum possible ways so that they will cross the river is? (boat wil carry only two at once)
a) 16
b) 17
c) 18
d) 19
Read Solution (Total 10)
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- we have 4 couple
solution:
1)first two husbands goes to another side
2)then one husband comes back
3)then one couple will go
4)then second husband comes back
so in this 4 ways 1 couple reach to another side
so for 4 couples there are 16 ways
a)16 is ans - 12 years agoHelpfull: Yes(60) No(11)
- 4 couples in 4 ways=4
4 husbands in 4c2 ways
4 womens in 4c2 ways
4+4c2+4c2=16 - 12 years agoHelpfull: Yes(32) No(4)
- guys minimum possible ways are 13. think practical....
- 9 years agoHelpfull: Yes(18) No(4)
- first there are 4 ways for a couple to reach another side one by one =4 ways
secondly 2 husband can go together
now there are 4 husband so we have to select 2 out of 4
4c2 ways= 4!/(4-2)!2!=6
thirdly 2 wives can go together
now there are 4 Wives so we have to select 2 out of 4
4c2 ways= 4!/(4-2)!2!=6
so 4+6+6=16
16 is answer - 12 years agoHelpfull: Yes(9) No(2)
- ans is 16.
they travel 1st husband can travel 3times
2nd husband can travel 2times
3rd husband can travel 1time
they travel 1st wife can travel 3times
2nd wife can travel 2times
3rd wife can travel 1time
4couples can travel 4times
total=16
- 12 years agoHelpfull: Yes(3) No(1)
- tow husbands will go together than one come back and carry his wife and then other one come and take a man and so on so ans should be 4*4=16
- 12 years agoHelpfull: Yes(3) No(2)
- ans is 16...
- 12 years agoHelpfull: Yes(2) No(1)
- we have 4 couple
solution:
1)first two husbands goes to another side
2)then one husband comes back
3)then one couple will go
4)then second husband comes back
so in this 4 ways 1 couple reach to another side
so for 3 couples we have 12 ways and for the fourth one one only one way.
so ans is 13 ways. - 6 years agoHelpfull: Yes(2) No(0)
- 4couples in 4 ways=4
4husbands in 4c2 ways
4womens in 4c2 ways
4+6+6=16 - 12 years agoHelpfull: Yes(1) No(1)
- Every husband can travel with others 3 husband and his own wife. so every husband has 4 options.
There are 4 husbands. So 4 * 4 (no. of husbands * no. of options) = 16 - 3 years agoHelpfull: Yes(0) No(0)
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