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In a class of 100 students,the number of students passed in english only is 46,in maths only is 46,in commerce only is 58.the number who passed in english and maths is 16,maths and commerce is 24,and english and commerce is 26,and the number who passed in all subjects is 7.Find the no of students who failed in all sub?
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- Ans:=9
n(E)=46,n(M)=46,n(c)=58,
n(E nd M)=16,n(M nd C)=24,n(E nd C)=26,
n(E nd M nd C)=7
here E->English,M->Math,C->Commerce
only n(E)=46-(16+26)=4
only n(M)=46-(16+24)=6
only n(C)=58-(24+26)=8
total no. of students who passed(any or any two or all )=4+6+8+16+24+26+7=91
no. of students who failed in all sub=100-91=9 - 12 years agoHelpfull: Yes(21) No(1)
- I think , statement should be
In a class of 100 students,the number of students passed in english is 46,in maths is 46,in commerce is 58.
According to given statement, there are more than 100 Students ( 46+46+58) who passed in one subject only whereas statement should be that out of total 100 students, 46 passed in English out of which some also passed in maths and/or commerce.
Only then solution is possible and then answer will be
9 students failed in all subjects. - 12 years agoHelpfull: Yes(19) No(1)
- answer came 9 its 100-91
- 12 years agoHelpfull: Yes(9) No(2)
- answer is 11 using pie diagram
- 12 years agoHelpfull: Yes(5) No(11)
- n(A U B U C) = n(A) + n(B) + n(C) - n(A N B) -n(B N C) - n(C N A) + n(A N B N C)
n(A U B U C)=100,n(A) =46, n(B) =46 n(C)=58
n(A N B) =16,n(B N C) =24, n(C N A)=26
calculate and find out (n(A N B N N C)
- 12 years agoHelpfull: Yes(4) No(9)
- Is the given data correct ?
the number of students passed in 'english only is 46',in 'maths only is 46',in 'commerce only is 58'. - 12 years agoHelpfull: Yes(3) No(3)
- ANSWER IS 100-91=9.
- 12 years agoHelpfull: Yes(3) No(1)
- i thnk question is incorrect.
- 12 years agoHelpfull: Yes(3) No(5)
- after geting n(A N B N C) anns will 100-n(A N B N C)
- 12 years agoHelpfull: Yes(2) No(4)
- ans is 91
using inersectn-union formula - 12 years agoHelpfull: Yes(1) No(5)
- ans
is 16 - 12 years agoHelpfull: Yes(1) No(5)
- pls mail me some ques as my campus day after tommorw
- 12 years agoHelpfull: Yes(0) No(3)
- my id is shyamleshd@gmail.com
- 12 years agoHelpfull: Yes(0) No(3)
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