4. A tree of height 36m is on one edge of a road of width 12m. It falls such that the top of the tree touches the other edge of the road. Find the height at which the tree breaks

• let the height at which it broke be Xmt
  let the length of other piece be Ymt which touches ground
  X+Y=36;
  Y^2 - X^2 = 144
  
  then on solving x=16mt
• 12 years agoHelpfull: Yes(32) No(5)
• let y be the height at which tree breaks.x be the remainin height
  x+y=36; y=36-x:
  xy=(36x-x^2);
  by theorem,
  y^2=X^2+(12)^2:
  x^2+y^2+2xy=36^2:
  substituting above values,
  72x=1152
  x=16
  therefore y=36-16=20
  ans:20
• 12 years agoHelpfull: Yes(10) No(14)
• X+Y=36 , y is measured from the ground...
  X^2-Y^2=144;
  X-Y=4;
  x=20; and Y=16;
  So height from ground, at which it broke be Y=16 meter
• 12 years agoHelpfull: Yes(7) No(1)
• suppose required height is x, so draw the triangle(easily u can)
  so u also can work out
  x^2 + 12^2=(36-x)^2
  =>x=16
• 12 years agoHelpfull: Yes(7) No(0)
• solve (36-x)^2-x^2=144;
  x=16
• 12 years agoHelpfull: Yes(6) No(2)
• x^2=12^2+(36-x)^2
  on solving
  x=20
  so ans will be 36-20=16
  
• 12 years agoHelpfull: Yes(5) No(0)
• 36-12=24m should be the ans....
• 12 years agoHelpfull: Yes(2) No(16)
• please anyone solve these equ
  
  x^2 + 12^2=(36-x)^2
• 8 years agoHelpfull: Yes(1) No(0)
• given h=36m w=12m
  let x be the height where the tree cuttoff
  from pythagerous theorem
  x^2+12^2 = (36-x)^2
  by solving this we get the value of x =16m
• 5 years agoHelpfull: Yes(1) No(0)
• answer is 24
  36-12=24.
• 5 years agoHelpfull: Yes(0) No(1)