n!has 13 zeros what is the highest & lowest value of n??

• 55/(5^1) + 55 /(5^2) =13 (for 55! value)
  so the range lies on btwn 55 ----59
• 11 years agoHelpfull: Yes(29) No(1)
• 5! = 120 (hence one 0)
  10! = (there are 2)
  15! = 3 zeros
  20! = 4
  30! = 6
  40! = 8
  50! = 10
  60! = 12
  65! = 13
  70! = 14
  
  hence highest value is 69!
  lowest value is 65!
  
• 11 years agoHelpfull: Yes(23) No(22)
• 59 AND 55
  ans:
  55/5=11
  11/5=2
  (IT WILL HAVE 13 ZEROS AT THE END)
  SIMILARLY FOR 56,57,58,59..
• 11 years agoHelpfull: Yes(3) No(0)
• min=65
  max=69
• 11 years agoHelpfull: Yes(2) No(13)
• In any product a zero will occur when ever a 2 and a 5 is multiplied. so number of zeros depends on number of 2's and equal number of 5's. As n! has 13 zeros, it must have 13 - 5's and 13 - 2's. 55! has 13 - 5's and 50 - 2's, but, only 13 zero's will occur.so, minimum value of n is 55. The maximum value of n! to get 13 zeros is 59!, because 60! will have 14 - 5's, so will result in 14 zero's.
• 8 years agoHelpfull: Yes(2) No(0)
• max=54
  min=50
• 11 years agoHelpfull: Yes(1) No(10)
• @ankit: please explain clearly.
• 11 years agoHelpfull: Yes(0) No(2)