. A cow and horse cost Rs 200000. Cow was sold at a profit of 20% and Horse was sold at a loss of 10%. Profit earned in the entire process was Rs 4000. Find the cost price of the cow

• if cost of cow is x ,cost of horse is (200000-x)
  120x/100+90(200000-x)/100=204000
  x=80000 rs.
  
• 12 years agoHelpfull: Yes(42) No(1)
• 20%ofx-10%(2,00,000-x)=4,000
  30% of x- 20,000=4,000
  30% of x=24,000
  10% of x=8,000
  so it is 80,000...so cost price is 80,000
  
• 12 years agoHelpfull: Yes(6) No(1)
• cost price of cow is rs80000
  
• 12 years agoHelpfull: Yes(2) No(3)
• let the cp of cow is x and horse is y then
  x+y=200000------(i)
  now as said cow sold 20%profit and horse sold 10% loss
  then 6x/5+9y/10=200400-----(ii)
  solving i and ii we will get
  x=132000 and y=68000
  
• 12 years agoHelpfull: Yes(2) No(12)
• x+y=200000
  20% of x -10% of(200000-x)=10% 0f 200000
  x=133333.333
• 12 years agoHelpfull: Yes(2) No(5)
• why we cant do this as:
  let c.p of cow =x
  then cp of hourse = 200000-x
  then,
  120/100*x-90/100*(200000-x)=4000
• 9 years agoHelpfull: Yes(1) No(1)
• cow horse cow horsecow horse cow horse
  yaaar koi doosra question hai ki nahi'
• 9 years agoHelpfull: Yes(1) No(0)
• profit=4,000
  profit=sp-cp
  4,000=sp-2,00,000 therefore sp=2,04,000
  let x and y be cow and horse
  x+y=2,00,000 ............... 1
  1.2x+0.9y=2,04,000 .............2
  
  by solving equ 1 and 2 ,we get
  
  x=80,000 & y=1,20,000
  cp of cow =80,000
• 9 years agoHelpfull: Yes(1) No(0)
• x-y/2=20-10/2=5
  i.e. p%=5%
  we know hat
  p%=profit/cp*100
  =>5=4000/5*100
  =80000
  
• 9 years agoHelpfull: Yes(0) No(0)
• let cp of cow be x.
  then cp of horse=200000-x.
  sp of cow=120*x/100=6x/5
  sp of horse=90(200000-x)/100
  profit=sp-cp
  4000=6x/5+180000-9x-200000
  x=80000rs
• 9 years agoHelpfull: Yes(0) No(0)