There are 2 trains A and B speeding towards each other at 50km/hr and 60km/hr respectively. When the two trains pass each other B has covered 120 km more than A. What is the distance between A and B initially?

• Let time taken to meet be t
  So,120=(60-50)*t
  so,t=12hrs
  So,total distance=110*12=1320
• 12 years agoHelpfull: Yes(30) No(3)
• Let A covers x distance and B x+120 while they meet after a certain time.
  =>x/50=(x+120)/60
  =>x=600.
  Therefore initial distance between A and B= 600+720=1320
• 12 years agoHelpfull: Yes(20) No(0)
• ans=1320
  if initial distance be=110 then b covers 10 km more
  b covered 120 more then initial distance=(120/10)*110
• 12 years agoHelpfull: Yes(5) No(2)
• x/50=x+120/60
  50X+6000=60x
  10x=6000
  x=600 km(ans)
• 12 years agoHelpfull: Yes(4) No(7)
• AT TIME T THEY JUST CROSSED EACH OTHER .
  SO DISTANCE TRAVEL BY A=D/50
  DISTANCE BY B=D+120/60
  TIME SHOULD BE SAME
  SO ANS IS 600...PLZ CHECK
• 12 years agoHelpfull: Yes(1) No(3)
• 720 km consider a as x and b 120 +x
  
• 12 years agoHelpfull: Yes(0) No(4)
• ans-220
  sol:-when both will meet the ratio of distances covered will be equal to ratio of their speed bcz they will spent same time.
  let distance between A & B is d
  since B has covered 120 km,then A has covered (d-120) km
  hence
  50/60=(d-120)/120
  d=120+50/60*120=220km
• 12 years agoHelpfull: Yes(0) No(5)