10 people are there they are shaking hands together how many handshakes possible if they are in no pair of

9+8+7+6+5+4+3+2+1=45 way(ans)
12 years agoHelpfull: Yes(8) No(13)
ans:45.bcaz=10th person handshaked to 9th,8th,7th,6th,5th,4th,3rd,2nd,1st persons.similar to all persons.so,9+8+7+6+5+4+3+2+1=45.
12 years agoHelpfull: Yes(4) No(8)
9
well since there is no repitition allowed therefore handshakes will go to the 10th person.... in all 9 handshakes.
12 years agoHelpfull: Yes(3) No(3)
ans=9
treat it as the problem of graph where n nodes are there and these nodes connected
with n-1 edges without a cycle
12 years agoHelpfull: Yes(3) No(4)
apply NCR

10C2= 10!/2!.8!=45
handshake possible =45 only :)
12 years agoHelpfull: Yes(2) No(3)
Sorry, yes it will b 9 ....bcoz no repitition
12 years agoHelpfull: Yes(1) No(3)

10 people are there,they are shaking hands together,how many handshakes possible,if they are in no pair of cyclic sequence