In the adjoining diagram, ABCD and EFGH are squres of side 1 unit such that they intersect in a square of diagonal length (CE) = 1/2. The total area covered by the squares is

A. Cannot be found from the information
B. 1 1/2
C. 1 7/8
D. None of these

• area of intersecting sq= 1/8
  area of both square=1+1=2
  total area cvrd by sqr=2-1/8= 15/8 ans c.
• 12 years agoHelpfull: Yes(24) No(5)
• 15/8 is d ans
• 12 years agoHelpfull: Yes(9) No(4)
• if the ans is 15/8 means ans c is correct rit..?? coz we can write 15/8 as 1 7/8 rit..>??
• 12 years agoHelpfull: Yes(9) No(0)
• using pythogerous theorem......
  CE = 1/2
  (1/2)/2 = 1/4
  so the sides r 1/4,1/4, x in d right angle triangle
  (1/4)^2 + (1/4)^2 = x^2
  so x = 1/ sqrt(8).
  area of intersecting square = x^2 = 1/8
  area of both square=1+1=2
  total area cvrd by sqr=2-1/8= 15/8
  ans c
• 12 years agoHelpfull: Yes(7) No(1)
• how do you know from where did 2 square intersect third one,it jus given 2 square intersect 3rd,
• 12 years agoHelpfull: Yes(6) No(0)
• area of square = (side)^2 = (diagonal/√2)^2
  so for big square (1)^2 = 1
  there are two big squares so..1 + 1 = 2
  then for the smaller intersecting square the diagonal value is only given,so
  area ((1/2)/√2)^2 = 1/8
  the total area covered by the squares is = 2 - (1/8) = (16-1)/8 = 15/8
• 11 years agoHelpfull: Yes(6) No(1)