roy is now 4 years older than erik & half of that amount older than iris if in 2 years roy will be twice as old as erik then in 2 years what whould be roys age multiple of iris age?

• let roy=x erik=y and lewis=z
  as per the first sentence.....
  x=y+4-------(1)
  x=z+2---------(2)
  after 2 yrs... roy=x+2 erik=y+2 lewis=z+2
  den as per d question-- x+2=2(y+2)------(3)
  solving we get--- x=6,y=2,z=4
  
  multiplication after 2yrs of roy n lewis is (6+2)*(4+2)=48
• 12 years agoHelpfull: Yes(9) No(1)
• Given data seems to be wrong.
  
  
  If E is present age of Erik, then
  present age of Roy = E+4
  Present age of Iris = E+2,
  then
  E+6 = 2*(E+4)
  E= -2 which is not possible.
• 12 years agoHelpfull: Yes(3) No(6)
• if E is erik presnr age so
  roy R=E+4
  iris R=1/2I+I=3/2I
  R+2=2(E+2)
  so solve equatio
  E=2
  R=6
  I=4
  SO R*I=24 ANS.24
• 12 years agoHelpfull: Yes(2) No(5)
• X=Y+4
  X=Z+2
  X+2=2*(Y+2)
  X=6,Y=2,Z=4,
  AFTER 2 YEAR
  8*6=48 ANS...
  
• 12 years agoHelpfull: Yes(2) No(1)
• 4/3 will b the correct answer
• 12 years agoHelpfull: Yes(1) No(2)
• roy is 1 n half times iris.
• 12 years agoHelpfull: Yes(0) No(0)
• let roy=x erik=y and lewis=z
  x=y+4,x=z+2
  x+2=2(y+2)
  solving we get, x=6,y=2,z=4
  ans z:(6+2)*(4+2)=48
• 12 years agoHelpfull: Yes(0) No(0)