if numerator increased by 25% & denominator decreased by 20% will give 5/4 what is original value?

• If original value is N/D . then
  1.25 N/ 0.8 D = 5/4
  N/D = (5*0.8)/(4*1.25) = 0.8= 8/10 = 4/5
  
  original value = 4/5
• 12 years agoHelpfull: Yes(9) No(0)
• let x/y
  (125x/100)/(80y/100)=5/4
  125x/80y=5/4
  25x/20y=1/1
  x/y=20/25=4/5
  
• 12 years agoHelpfull: Yes(4) No(1)
• (N + 0.25N)/(D - 0.2D)=5/4
  N/D(1.25/0.8)=5/4
  N/D = 4/5
• 12 years agoHelpfull: Yes(2) No(1)
• (x+(1/4)x)/(y-(1/5)y)=5/4.
  By solving above we get: 4/5.
• 12 years agoHelpfull: Yes(2) No(1)
• 1.25x/0.8y=5/4
  x/y=5*08/(4*1.25)
  =4/5
• 12 years agoHelpfull: Yes(2) No(1)
• after increase and decrease as given in question the equation is
  1.25X/0.8Y=5/4(where the original was X/Y)
  so easily u can find out
  5X=4Y
  =>X/Y=4/5(Ans.)
• 12 years agoHelpfull: Yes(2) No(0)
• x+.25/x-.20=5/4
  4(x+.25)=5(x-.2)
  then
  x=2 ans
• 12 years agoHelpfull: Yes(0) No(3)