two friends A,B are running up hill and then to get down! length if road is 440 yards A on his return journey met B going up at 20 yards from top, A has finished the race .5 minute earlier than B, then how much time A had taken to complete the race.

• A gains 20 yards over B in it's down the hill journey. So for entire journey A will have a lead of 40 yards over B.
  now, when A is at destination B is 40 yards behind which B will cover in 5 minutes.
  so, by unitary method we get..
  For B, 40 yards in 5 minutes
  therefore,1 yard in 5/40 minutes
  therefore,880 yards in (5/40)*880=110 minutes.
  Now b takes 110 minutes so A will take 105 minutes.
• 10 years agoHelpfull: Yes(33) No(9)
• distance between A and B is 40yards.
  time is 0.5 min. so to cover 440yards time taken is 5min30sec.
  Hence for completion on race 880yards which implies 11min by A to complete.
• 11 years agoHelpfull: Yes(19) No(11)
• Length of the road to go to top =440 yards
  then to reach the top and again reach down it will take 880 yards to complete
  A finishes the distance of 880 yards 5 mins before B to complete.
  If A is at destination [(i.e) at 880th yard]
  Then B must be at 840th yard
  So diff Between the two are 40yards.
  If A finishes the total distance 5mins before B then B takes 5 mins to finish 40 yards.
  therefore B's total time taken to finish the dist = 22 x 5 [(i.e)40 yards =50]
  so 22 x 40 =880 therefore 22 x 5=110
  
  If B takes 110 mins to complete then A should complete 5 mins before B
  
  Ans : 105 mins
• 10 years agoHelpfull: Yes(9) No(5)
• 105 minutes.
  b lacks 40 yards n covers it in 5 minutes.
  bcovers 8 yards in 1 min
  hence 880 yards in 110 min.
  a takes 5 min less than b ..hence 105 minutes
• 10 years agoHelpfull: Yes(9) No(4)
• Diff b/w A and B = 40 yards
  Diff in time = 5
  so for 440 yards, it will 55 mins
• 11 years agoHelpfull: Yes(6) No(18)
• first we have to calculate speed of A
  speed of A is (distance bw A and B)/5 min =40/5=8.
  time A had taken to COMPLETE THE RACE =(Total distance/speed)=880/8=110
• 10 years agoHelpfull: Yes(3) No(6)
• first we will calculate speed of
  the distance covered by A is 840 and the distance coverd by B is 800
  A takes time (t-5)
  B takes time t
  so equate both distance
  840(t-5) = 800(t)
  t = 105 min
• 10 years agoHelpfull: Yes(3) No(6)
• Length of the Road = 440 Yards. [one side]
  A covers 460 yards when B covers 420 yards.
  When A covers 880 yards B covers (420/460) * 880 yards.
  B covers (1 - 21/23) * 880 yards in 5 minutes.
  B covers 880 yards in 5*23/2 = 57.5 minutes.
  Thus A covers the distance in 52.5 minutes.
• 10 years agoHelpfull: Yes(3) No(2)
• 11min
  simple unitary mthd
  .5 min=40 yards
  (.5*880)/40=880yards
  11 min=880 yards
• 9 years agoHelpfull: Yes(3) No(2)
• 2 persons running up and down the hill.
  length of road = 440
  
  A met B while he coming down. while A coming down B was geting up and he is 20 yards below the road of up journey
  
  which means B coverd 420 yards. at same time A covered up journey+20 yards from top to meet B
  
  i.e while B covers 420 yards, A covers 440+20 yards and he met B at that point
  
  B=420 yards, A= 460 yards
  A completes 5 min before B . so the diff b/w them 40 yards .
  
  it took 5 min for B to get to A at finish line which is 40 yards in 5 min which means 5/40 min
  
  for total distance, 880yards , 5/40 x 880= 110
  110 is for B since we get the 40 yard in 5 min for B person not A
  so A takes 105 min
• 9 years agoHelpfull: Yes(2) No(0)
• When A travels 460m (=440+20),
  
  B travels 420m (=440-20). So, ratio of speed = 460:420
  
  = 23:21.
  
  Let A's speed be 23x, and that of B's be 21x.
  
  => 23x = ((2 * 440) / t) which implies 23t = 880/x;
  
  => 21x = ((2 * 440) / (t+5)) which implies 21(t+5) = 880/x.
  
  From these two equations, 23t = 21(t+5). Solving, t = 52.5
• 7 years agoHelpfull: Yes(1) No(0)
• 5.5 mn will be ans....its so lengthy
• 6 years agoHelpfull: Yes(0) No(1)