a tiger is 50 of its own leaps behind a deer, the tiger takes 5 leaps per minute to the deer's 4. if the tiger and the deer cover 8m and 5m per leap respectively, what distance will the tiger have to run before it catches the deer?

• ans =800
  tiger is 50 leaps of own behind that means tiger 50*8=400 m behind to deer
  again in one minute tiger covers 8*5=40 and that deer 4*5=20
  now after 20 minute dear will cover 20*20=400 and tiger 40*2=800
  as tiger has to cover 400 extra so 800 is the answer
• 11 years agoHelpfull: Yes(23) No(1)
• tiger is 50 of its own leap behind and covers 8m per leap
  So he iz 50*8=400m behind
  his speed = 5 leaps per min = 5*8= 40 m per min
  deer covers 5m per leap
  speed of deer = 4 leaps per min = 4*5 = 20 m per min
  SO speed of tiger is double than deer
  till the time tiger covers 800 m deer covers only 400 m
  tiger was 400m behind so upto when he covers 800m he will catch the deer
  So, ans= 800 m
• 11 years agoHelpfull: Yes(9) No(0)
• 50 leaps of tiger = 50*8 =400 m
  so the at first distance b/w tiger and deer is 400m.
  also tiger cover 5 leaps i.e 5*8=40 m/min
  and deer cover 4 leaps i.e 4*5=20 m/min
  now let after x min tiger catch the deer.
  in x min tiger cover 40x+400 m.
  and deer cover 20x m.
  so, 40x-400=20x
  or; 20x=400
  or, x=20min
  so tiger have to complete 40*20=800 mtr
  
• 9 years agoHelpfull: Yes(4) No(0)
• tiger-5*8=40m/min 80 120
  dear-4*5=20m/min +50=70 90 110
  they will coincide at 100m in 2min 30 sec
  ans is 100 m
• 11 years agoHelpfull: Yes(3) No(4)
• as is C. 800M
• 11 years agoHelpfull: Yes(1) No(3)
• 250+500=750 m
• 11 years agoHelpfull: Yes(0) No(1)
• the options given are
  a.600m
  b.700m
  c.800m
  d.1000m
  e.1200m
• 11 years agoHelpfull: Yes(0) No(3)
• it is given in the ? that tiger have to run before it catches the deer so i think only 400 is the ans. can someone explain me correclty
• 9 years agoHelpfull: Yes(0) No(0)