john walks on an escalator at a rate of 5 steps per second and reaches the other end in 10 secs. while coming back , walking at the same speed he reaches the starting point in 40seconds . what is the number of steps on the escalator?

• ans must be 80
  speed of john 5 steps per second
  let speed of escalator be x steps per second
  his speed while going up (5+x) per second
  while coming down speed will be (5-x) per second
  so (5+x)*10=(5-x)*40 by using distance = speed*time
  giving x= 3 steps per second
  so distance = (5*3)*10=(5-3)*40 = 80 steps
• 11 years agoHelpfull: Yes(25) No(0)
• starting tym step is total 50
  and when conig back it is 200
  so tatal step is 250
• 11 years agoHelpfull: Yes(8) No(6)
• ans 80 steps
  
• 11 years agoHelpfull: Yes(2) No(0)
• the answer given is 40
• 11 years agoHelpfull: Yes(1) No(2)
• its a que of to and fro so 2xy/x+y,
  2*10*40/10+40=16 ans
  
• 11 years agoHelpfull: Yes(0) No(7)