A man can hit the target once in four shots If he fires 4 shots in succession what is the

ans: 1-missing all four times .
1-((3/4)*(3/4)*(3/4)*(3/4))=175/256
9 years agoHelpfull: Yes(16) No(0)
required probability is 1- (probability he miss all time)
i.e 1-(3/4)^4
175/256
9 years agoHelpfull: Yes(5) No(1)
The target is not hit only when he is not able to hit it in any of the four shots. So the probability that he will hit target = 1 - (probability that he will not hit the target in any of the four shots)
= 1 - (3/4)*(3/4)*(3/4)*(3/4)
= 1 - 81/256
= 175/215
9 years agoHelpfull: Yes(3) No(0)
after 4 shots..definetly he hit the target. so the probability is 1. there is no chance of missing after 4 shots.
9 years agoHelpfull: Yes(2) No(2)
ans is - 1
9 years agoHelpfull: Yes(0) No(3)
A man can hit the target once in four shots---that means if he fire four shots then definitely he hit 1, and here we require the probability of hitting.
so ans is =1
9 years agoHelpfull: Yes(0) No(2)
once in four shots means.he will hit once if he fires 4 shots.
so the probility is 1/4 of hitting.
so he fired four shots succession .that means 1/4*1/4*1/4*1/4=1/256 is rite
9 years agoHelpfull: Yes(0) No(1)

A man can hit the target once in four shots. If he fires 4 shots in succession, what is the probability that he will hit target ?

Options
1) 1
2) 1/256
3) 81/256
4) 175/256